I got a question from a user called Bastiaan. He had found my site while searching for ‘cut from end of line Linux’ and landed on the Using cut – shellscript string manipulation article. I haven’t received a lot of feedback on it, but am happy with the feedback I have and the amount of visits it gets. As I’ve said before if no one else reads The Linux Blog I still use it as a reference, so I am glad people are finding it useful. Anyways, Bastiaan’s problem was he works in a University and has a file with A LOT of DNA records in it. He needed to grab the last 50 characters of each line, regardless of the line length. After some correspondence we came up with a solution.
I have experience in doing this sort of thing in other languages such as PHP but not bash. Here is what I came up with for bash:
cat find.txt | while read i; do echo $i | \
cut -b $((`echo $i | wc -c` - 50))-; done;
While this was really quick to write it is not the most efficient way in the world. It has to read each line, echo it out, calculate the length of the line, subtract 50 from it. Again, does the job but not very gracefully.
Bastiaan then had told me he reversed the whole file and then was processing that with cut. I have heard of tac, to reverse entire files, but not had never heard of rev. Using rev I assumed that he was running something like the following:
rev file.txt > rev_file.txt
cat rev_file.txt | cut -c -50 | rev
That will get you the last 50 characters from each line (well, really the first 50 of a reversed file) That works pretty good so the final solution was to try to stream line it a little bit so that it could be done in one step.
rev file.txt | cut -c -50 | rev > out.txt
So there you have it, if you’re looking to use cut to “cut” characters from the end of the line, the above will cut 50 characters off of the end. Obviously you can remove the last “> out.txt” to get the output on the screen.
Hope this helps some one, and thanks to Bastiaan for the question!